Resenje jednacine
[dispmath]\sin\left(x+\frac{\pi}{3}\right)=-1[/dispmath] koje pripada intervalu [inlmath](4\pi,6\pi)[/inlmath] je:
[inlmath]\displaystyle A)\;\frac{7\pi}{6}\quad[/inlmath] [inlmath]\displaystyle B)\;\frac{31\pi}{6}\quad[/inlmath] [inlmath]\displaystyle C)\;\frac{35\pi}{6}[/inlmath]
ja sam radio ovako:
[dispmath]x+\frac{\pi}{3}=\frac{3\pi}{2}[/dispmath] pa sam stigao dovde:
[dispmath]x=\frac{7\pi}{6}+2k\pi[/dispmath] sta dalje ? unapred hvala