Nezavisne varijable [inlmath]X[/inlmath] i [inlmath]Y[/inlmath] imaju isti zakon razdiobe [inlmath]X,Y\sim[/inlmath]
[dispmath]\begin{pmatrix}
0 & 2 & 3\\
0.2 & 0.5 & 0.3
\end{pmatrix}[/dispmath] Odredite razdiobu slucajne varijable [inlmath]2X\cdot Y[/inlmath]
ja sam to ovako rijesila, ali neznam je li tocno
[dispmath]2(0\cdot0)=0\hspace{5mm}2(0\cdot2)=0\hspace{5mm}2(2\cdot0)=0\hspace{5mm}2(3\cdot0)=0\hspace{5mm}2(0\cdot3)=0\\
2(2\cdot2)=2\cdot4\hspace{5mm}2(2\cdot3)=2\cdot6\hspace{5mm}2(3\cdot2)=2\cdot6\hspace{5mm}2(3\cdot3)=2\cdot9[/dispmath] i onda sam
[dispmath]P(2X\cdot Y=0)=0.36\hspace{5mm}P(2X\cdot Y=8)=0.25\hspace{5mm}P(2X\cdot Y=12)=0.3\hspace{5mm}P(2X\cdot Y=18)=0.09[/dispmath] pa sam dobila [inlmath]2X\cdot Y\sim[/inlmath]
[dispmath]\begin{pmatrix}
0 & 8 & 12 & 18\\
0.36 & 0.25 & 0.3 & 0.09
\end{pmatrix}[/dispmath]