[inlmath]3)[/inlmath]
[dispmath]A=\left[\begin{matrix}
1 & 4 & -2 \\
0 & 5 & -2 \\
-1 & 4 & 0
\end{matrix}\right][/dispmath]
[dispmath]\left(-\lambda^3+6\lambda^2-11\lambda+6\right):(\lambda-1)=(1-\lambda)(\lambda-3)(\lambda-2)[/dispmath]
- [inlmath]\lambda=1[/inlmath]
alg.krat [inlmath]=[/inlmath] geo.krat [inlmath]=1[/inlmath]
[inlmath]x_1=s[/inlmath]
[inlmath]x_2=\frac{1}{2}s[/inlmath]
[inlmath]x_3=s[/inlmath]
- [inlmath]\lambda=2[/inlmath]
alg. [inlmath]=[/inlmath] geo. [inlmath]=1[/inlmath]
[inlmath]x_1=\frac{2}{3}s[/inlmath]
[inlmath]x_2=\frac{2}{3}s[/inlmath]
[inlmath]x_3=s[/inlmath]
- [inlmath]\lambda=3[/inlmath]
alg. [inlmath]=[/inlmath] geo. [inlmath]=1[/inlmath]
[inlmath]x_1=x_2=x_3=s[/inlmath]
Ako je točno, preostaje samo uva tri rješenja staviti u matricu, a to nije problem...