[inlmath]\sin\left(\alpha+\beta\right)=\sin\alpha\cos\beta+\cos\alpha\sin\beta[/inlmath]
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bobanex za post:
Daniel
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od bobanex » Petak, 30. Jun 2017, 21:21
[dispmath]x_1=\frac{2k\pi}{3}\\
x_1\in\left\{0,\frac{2\pi}{3},\frac{4\pi}{3}\right\}\\
x_2=2k\pi\\
x_2\in\left\{0,2\pi\right\}[/dispmath] Na ove dve nule sam mislio.
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od Daniel » Petak, 30. Jun 2017, 22:41
Aha, nesporazum. OK.

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